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100x^2-900x=1000
We move all terms to the left:
100x^2-900x-(1000)=0
a = 100; b = -900; c = -1000;
Δ = b2-4ac
Δ = -9002-4·100·(-1000)
Δ = 1210000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1210000}=1100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-900)-1100}{2*100}=\frac{-200}{200} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-900)+1100}{2*100}=\frac{2000}{200} =10 $
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